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 #33246  by Melissa
 
3 MEN GO INTO A MOTEL. THE MAN BEHIND THE DESK SAID THE ROOM IS £30 SO EACH MAN PAID £10 AND WENT TO THE ROOM.

A WHILE LATER THE MAN BEHIND THE DESK REALIZED THE ROOM WAS ONLY £25

SO HE SENT THE BELLBOY TO THE 3 GUYS' ROOM WITH £5.

ON THE WAY THE BELLBOY COULDN'T FIGURE OUT HOW TO SPLIT £5 EVENLY BETWEEN 3 MEN, SO HE GAVE EACH MAN A £1 AND KEPT THE OTHER £2 FOR HIMSELF.

THIS MEANT THAT THE 3 MEN EACH PAID £9 FOR THE ROOM, WHICH IS A TOTAL OF £27, ADD THE £2 THAT THE BELLBOY KEPT = £29.

WHERE IS THE OTHER POUND?

 #33250  by saunby
 
Ahh Ive heard this one before but I cant remember the answer without looking on the internet xD

Its so messed up I mean however you look at it, it just doesnt add up :(

The man has 30 then takes 5 out of that to give to the boy so the man has 25

Then the boy takes 2 and gives the men 3

Which means that the men got 3 on top of the 25 which is 28 plus the 2 that the boy took...

But then if you look at it the way it is described which is that if they all pay 10

10+10+10=30

And they all get 1 back

9+9+9=27

And the boy still has 2

27=2=29


I mean its just like wtf..


But the thing is and I just half figured this out and half remembered it. the number of 27 is wrong because we do the sum wrong by instinct.


We add stuff up e.g. the men each spent 9 quid, that equals 27 and the bell boy has 2 thats 29.

But you need to reverse the sum e.g. Out of the original 30 quid, they get 3 quid back so in effect they have spent 27 (even if the bell boy did take 2 quid, besides the point here) once you subract that 2 quid from 27 you are left with the 25 in the till.


I have to admit though, this is such a good question, makes you think and think and think hahaha

 #33253  by Darko
 
This is just a trick question that can be solved logically using basic mathematics. Okay, so three men go into a motel and each pay $10 for a room, totalling $30. The actual price is $25. So the bellboy takes $5 in change to the three men to split up but gets confused. I suppose because he's immature, possibly going through a tough time with his divorce settlement and custody battle. He also probably has a problem with gingivitis on top of it all. But anyway, he decides to pocket $2 to save everyone some trouble and to maybe get a snack out of the vending machine for later since he has to work overtime trying to pay for his overpriced one-bedroom apartment in the Bronx. The other $3 is split among the three men, each obtaining $1. So, that means that they each paid $9, right? Well:

$30 to start with.
- $5 taken back to men
= $25 left
$5 taken back to men
- $3 given away
- $2 in pocket of bellboy
= $0! There is no extra dollar! It is a trick!

 #33255  by Melissa
 
The trick is the 5 remaining is subtracted backwards
taking off 3 when he is givng it thus remainder is two

 #33261  by Greed
 
This trick gets old...

 #33276  by Grimm
 
ya it is old. to solve u just have to work backwards

 #33278  by FlapJack23
 
The taxman took the extra pound.

 #33283  by Richard
 
Hawk wrote:This trick gets old...
Dont do it then :roll:

 #33287  by Phoenix
 
Richard wrote:
Hawk wrote:This trick gets old...
Dont do it then :roll:
I was going to say the same thing.

I personally hadn't seen it before, so even if its "old" i'm happy you posted it.

 #33289  by Chantelle
 
the two is to throw you off course..

They paid £9 each and got £1 each refunded.. therefore £30

the £2 is just him pocketting out of the £27 it could have been £8

 #33290  by Greed
 
Richard wrote:
Hawk wrote:This trick gets old...
Dont do it then :roll:
Thats why I didnt give away the answer dont j00 see?

 #33291  by Chantelle
 
Or better even

If it causes just disdain why bother posting.

ps whats all This J00 business?

 #33292  by Darko
 
Came from calling people jews without seeming too racist.
Now its in the place of the word you
All part of typing coolness

 #33293  by Melissa
 
Hawk wrote:This trick gets old...
Sorry

Give me your email address and in future ill run em all past j00

 #33295  by Greed
 
U guys are makin' 2 big a deal out of 1 post IMO. Just saying that this trick gets old isn't really that bad that u start a little battle against it Yeesh...

 #33297  by saunby
 
Dude, yeah okay maybe they over reacted a little to your post but first off let us not start a flame war, but maybe you could have said something like I had which was that I have seen it before but it is a good brain teaser.

Your post was a little blunt and come to think about it, if I were Mel I would take it slightly offensively, shes posted it here for people to look at and you have stepped in and dismissed her post by saying it is old, it is not her fault you have seen it before and you think it is old, also the ellipsis (...) makes it look a bit arrogant and stuff.

Anyways I seem to have contradicted myself slightly as I said not to start a flame war, anyways thats how I see it, to be quite honest the matter does not really need anymore said on it Or you will be starting a flame war and it would be a shame to have to lock this topic.

 #33298  by Fazz
 
ok, i got some

first 1 is a maths 1

Whats the minimun number of weights you need to weigh every number in grams up 2 13 on dish scales



Now a psychological riddle


3 guys have a gun each and all wana kill eachother, they will fire in rotation untill only 1 is left alive. there names are greg, bob and jimmy

greg knows he can only hit his target 1 time outa 3
bob can always get 2 outa 3
and jimmy can get some1 with every shot

greg gets first shot, what shud he do (no1 say run away, lol)


This 1 is very mathamatical, and i will be seriously impress if any1 can get it:


Image

that image is 2 non-readable, if any1 wants me 2 email it 2 them, tell me and i will

 #33299  by saunby
 
Greg should shoot Jimmy as he is most accurate, Greg isnt accurate but it is the best risk he can take, if he is lucky, Jimmy will die and then Bob who is accurate most of the time will have no option but to shoot at Greg as he is the only man left, it is unlikely that Greg will survive but yet possible, assuming he does miss, Greg can then take a shot at Bob and hopefully hit him, it is again unlikely but still possible.

That was my serious answer...

My silly one would be:

Greg should take his laptop out and ultimate h4x0r Bob thus stealing his 2/3 accuracy to add to his 1/3 accuracy, this means that now:

Jimmy = 3/3 shot, always accurate
Greg = 3/3 shot, always accurate
Bob = 0/3 shot, unfortunately he can no longer hit anything he is aiming at.

Greg then shoots Jimmy thus killing him and Bob attempts to shoot Greg but obviously misses, Greg then kills him as well.

Alternatively, Greg could get his laptop out again and h4x0r the Army's secret intelligence base and call in an airstrike on Jimmy and Bob labelling them as terrorist threats to the country.




:D

 #33300  by Fazz
 
lol, wrong 2 both

 #33303  by Darko
 
Fazz wrote: Whats the minimun number of weights you need to weigh every number in grams up 2 13 on dish scales
The grammar of that is unreadable.

 #33312  by Kenshin
 
greg shud shoot jimmy. then bob shud shoot jimmy. then tht means theres only 2 left because 1/3 +2/3 = 3/3. then its gregs turn he shud shoot bob then bob shoot greg. in theory bob should win. ( i dont actually fully understand the question).

 #33314  by Melissa
 
Actually sod this im editing

I am not biting my tounge any longer

I personally made a joke , a joke to your attempting ridiculing post

it was a joke, and you have the audacity to make a comment back..


Clearly your not old enough to take what you give..

It doesnt take much manners to be nice , it seems like alot of the time here people would rather do the opposite, to others as well as me..

I had enough of this place.

 #33315  by jawfin
 
1. If the weights are cardinal then its a very simple binary question. The weights needed would be the powers of 2; being 1, 2, 4 and 8 grams: so 4 weights, also this will allow all the weights up to 15 grams too. If the weights can be fractions or even worse, irrational numbers then it would take some serious calculus to solve, beyond my abilities.

2. As you said its a psychological puzzle, and so much not a logical one, we have to take into mind the thinking of the other shooters; specifically that Greg should shoot at Bob knowing that Jimmy doesn't consider Greg a threat. Again there is some missing information to this one; is Greg allowed to shoot at no-one? Into the ground? In which case, he should do just that; or not fire at all; again witht the same logic that neither Bob nor Jimmy consider Greg a threat.

3. Cannot see the image, are these Greek letters? Do they represent 10s and units of length? What exactly are we trying to find here? It seems to be a simple problem of triangle 180 degree math/similar triangles, with a bit of sin/cos/tan ratios and perhaps parallel line Z and U rules, and worst case some min/max intergral/calculus mathematics. Also it looks like its been scanned out of a high school math book lol.

 #33317  by jawfin
 
OK then, here's my 3...

1. In the sock drawer there are 15 blue socks and 15 green socks. It is pitch black and the colors cannot be discerned. How many socks need to be taken out to ensure you have at least a pair of the same color?

2. There's a compitition for $1,000 with three contestants; A, B & C. They are lined up, one behind another so that A cannot see anyone, B can see A and C can see both A & B (and what color hat they are wearing). Each of them have been given a hat that they are wearing and of which they cannot see, and they have been informed that among the three of them there is either 2 blue and 1 red hat, or 1 blue and 2 red hats. The winner of the compitition is he that can guess what color hat they have. They have 1 minute to work it out. In the last second one of them answers the question properly. Remembering the way they are lined up, who is the winner and how does he know?

3. Four snails sit on the four corners of a square, each facing the snail to the left. At the same time they all start moving toward the snail they are looking at, at the same speed, so that they each follow a spiral path to the center. How far did each snail travel before they met in the middle?

In regard to the missing quid puzzle, it is one of my favourites and the one I usually come out with first when prompted for a puzzle (these other 3 come next). It never gets old and is an excellent display of confusing simple math with language. Everyone should at sometime be challenged with this one, and although I have personally been aware of it for over 20 years I never get tired of seeing it, or watching people try to solve it. It is the all-time greatest puzzle; for nothing else it is worth memorising.

 #33320  by Fazz
 
Jawfin wrote:
In which case, he should do just that; or not fire at all; again witht the same logic that neither Bob nor Jimmy consider Greg a threat.
.
correct, and if ya want ill email u the pic for the last 1, as it dont work on this