This forum is for all the topics that don't fit anywhere else. Post anything from Hello's to Web Links.
 #49675  by Greed
 
I am a mathematical genius and I have figured out a way 2 make 2=1!

a=1
b=1


a=b
multiply by a

a^2=ab
subtract b^2

a^2-b^2=ab-b^2
Factor

(a-b)(a+b)=b(a-b)
Divide by (a-b)

a+b=b
Substitute

1+1=1
2=1?!?!?!?!


Can u figure out the flaw?

 #49676  by Necros
 
...I'm pretty sure you just did all the math...completely wrong, because there is no possibly way that you could make it so that a=b can become 2=1...unless I'm wrong here. Someone else good at math care to look this over @_@

Edit: Is the flaw in when you subtracted b^2? Cuz I have no idea why you did that or where b^2 even came from.

 #49677  by Pyra
 
@_@ As if math didn't confuse me enough already.

 #49678  by Greed
 
Necros wrote:Is the flaw in when you subtracted b^2? Cuz I have no idea why you did that or where b^2 even came from.
No thats not the flaw... as long as you do it to both sides of the equation it is valid. Good guess though.

Its actually really simple. People like me just make it look hard.

 #49680  by Falcon
 
Yeah, I don't know what you did wrong, but I can guarntee you that 2 does NOT equal 1. I'm sure if this were possible, highly payed mathematicians would've figured it out many many years ago (no offense to you Hawk.)

 #49681  by Chantelle
 
a-b = 0 but you cannot divide by that


illegal move

edit oops Jawfin already spotted :oops:

 #49683  by Greed
 
Jawfin and Chantelle are CORRECT!!!!!!! YAY!!!!!!!!

 #49691  by Necros
 
*Feels stupid* :(

 #49698  by FlapJack23
 
You don't even have to divide. If you plug in a and b, you get:
(1-1)(1+1)=1(1-1)
(0)(2)=1(0)
0=0

So you did the third to last step wrong.

 #49704  by Greed
 
Well yea... thats basically the same thing though...

 #49741  by Grimm
 
the answer is that there is no solution for 3 reasons:

the reason stated above by multiple people

if a and b were both known to equal 1, they would be represented by the same variable.

the domain of such an equation would require that if a=1, b can be any real number that does not equal 1.

 #49788  by Cross
 
cake

 #49794  by Delev
 
So much for showing off my 100 percent'ing of my algebra benchmarks and mid-term exam :roll:
Even though I found the same flaw as chantelle and jawfin <_>.

 #49799  by Melissa
 
the disguise is surely the algebra..

strip it back to numbers the division by zero would normally be alarming..
Well I say alarming, I don't mean you'd freak out et el. I mean you;d recognise it!